Sharee Doak: you need to define "at this moment" before the question could be answered..
Elvie Drumgoole: N 50 E: 50 degrees East of NorthS 80 E: 80 degrees East of SouthAngle between trajectory of the two boats = 180 - 50 - 80 = 50°Let d = distance between the two boatsUsing Cosine Lawd² = 56² + 48² - 2*56*48*cos(50°)d² = 1984.37381d = 44.5 km...Show more
Hilton Paiva: Position of Boat A relative to start point:A = 56cos50N + 56sin50EPosition of Boat B relative to start point:B = 48cos100N + 48Sin100EPosition of Boat B relative to Boat AAB = (48cos100 - 56cos50)N + (48sin100 - 56sin50)EAB = - 44.33N + 4.37E|AB| = √(83.27² + 34.56²) = 44.5kmThe distance between the boats is 44.5 km......Show more
Dulcie Edis: Nothing they Haven't left yet.
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